Question 1086364
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{{{y^2+3y}}} = {{{1}}}   ====>   {{{y^2 + 3y - 1}}} = 0  ====>

Apply the quadratic formula

{{{y[1,2]}}} = {{{(-3 +- sqrt(3^2 + 4*1))/2}}} = {{{(-3 +- sqrt(13))/2}}}.


There are two solutions:  {{{y[1]}}} = {{{(-3 + sqrt(13))/2}}}  and  {{{y[2]}}} = {{{(-3 - sqrt(13))/2}}}.
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On quadratic formula see the lessons 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/Introduction-Into-Quadratics.lesson>Introduction into Quadratic Equations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/proof-of-quadratic-by-completing-the-square.lesson>PROOF of quadratic formula by completing the square</A>

in this site.


Also, you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this textbook under the topic "<U>Quadratic equations</U>".