Question 1086326
<pre>
{{{a/b=c/d=e/f}}} let each of those equal to k. Then

{{{a=bk}}}, {{{c=dk}}}, {{{e=fk}}}

{{{((bk)^3+(dk)^3+(fk)^3)/(b^3+d^3+f^3)}}}

{{{(b^3k^3+d^3k^3+f^3k^3)/(b^3+d^3+f^3)}}}

{{{(k^3(b^3+d^3+f^3))/(b^3+d^3+f^3)}}}

{{{(k^3(cross(b^3+d^3+f^3)))/(cross(b^3+d^3+f^3))}}}

{{{k^3}}}

So 

{{{(a^3+c^3+e^3)/(b^3+d^3+f^3)}}}{{{""=""}}}{{{k^3}}}{{{""=""}}}{{{a^3/b^3}}}{{{""=""}}}{{{c^3/d^3}}}{{{""=""}}}{{{e^3/f^3}}}

Edwin</pre>