Question 1086356
There are 56 possible combinations choosing 5 cards out of 8 total (A,B,C,D,E,F,G,J) where J is the joker.
There are 21 possible combinations choosing 5 cards out of 7 total.
(A,B,C,D,E,F,G) where there is no joker.
So in 21 of the 56 outcomes, the joker is in the B hand. 
So in the A hand,
{{{P=35/56=5/8}}}