Question 1083167
{{{r-s=x-5-4x-2=-3x-7}}}
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{{{r*s=(x-5)(4x+2)=4x^2+2x-20x-10=4x^2-18x-10}}}
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{{{r+s=x-5+4x+2=5x-3}}}
So when {{{x=1}}},
{{{r+s=5(1)-3=5-3=2}}}