Question 1086224
Inner radius is {{{x}}}.
Outer radius is {{{x+1}}}.
So then,
{{{V=pi(R[o]^2-R[I]^2)*L}}}
{{{V=pi((x+1)^2-x^2)L}}}
{{{V=pi(x^2+2x+1-x^2)L}}}
{{{V=pi(2x+1)L}}}
Substituting,
{{{V=pi(2x+1)(150)}}}
{{{highlight(V=150pi(2x+1))}}}{{{in^3}}}