Question 1086233
 h(x)=x^3-5x^2+4x
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For h(-2), sub -2 wherever there's an x
h(-2) = (-2)^3 - 5*(-2)^2 + 4*(-2) = -8 - 20 - 8 = -36
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Do the others the same way.

<pre>

Table
 x   |  h(x)
-2      -36
-1
 0
 1
 2
 3
 4
 5

</pre>
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