Question 1085979
So for the 60km NE, it traveled 60(sqrt(2)/2) north and east.
For 6 hours, it traveled {{{6*96=576}}}{{{km}}} north.
So all together it traveled,
East : {{{E=30sqrt(2)}}}{{{km}}}
North: {{{N=30sqrt(2)+576}}}{{{km}}}
The magnitude would be the square root of the sum of the squares of E and N,
{{{M=sqrt(E^2+N^2)=sqrt(1800+576^2)}}}
and the angle,
{{{tan(theta)=N/E=(30sqrt(2)+576)/(30sqrt(2))}}}
where 0 degrees is due East.
Work those two out for the answer.