Question 1086131
I'll do one, you do the other the same way.
{{{a[10]=a[1]+(10-1)d}}}
{{{38=11+9d}}}
{{{9d=27}}}
{{{d=3}}}
So,
{{{a[2]=a[1]+(2-1)d=11+(1)3=11+3=14}}}
{{{a[3]=a[1]+(3-1)d=11+(2)3=11+6=17}}}
{{{a[4]=a[1]+(4-1)d=11+(3)3=11+9=20}}}
Continue this until you get all 10 terms.