Question 1086076
<font color="black" face="times" size="3">Point Slope Form:


{{{y-y[1] = m(x-x[1])}}}


{{{y-y[1] = 3(x-x[1])}}} Replace m with the given slope 3


{{{y-y[1] = 3(x-(-4))}}} Plug in {{{x[1] = -4}}} which is the x coordinate of the point the line goes through


{{{y-(-1) = 3(x-(-4))}}} Plug in the y coordinate {{{y[1] = -1}}} of the point the line goes through. Now solve for y.


{{{y+1 = 3(x+4)}}}


{{{y+1 = 3(x)+3(4)}}}


{{{y+1 = 3x+12}}}


{{{y+1-1 = 3x+12-1}}} Subtract 1 from both sides


{{{y = 3x+11}}} Answer in slope intercept form. We see that the y intercept is 11, meaning that the point (0,11) is also on the line. 


Graph:
{{{ graph( 500, 500, -10, 10, -5, 15, 0,3x+11) }}}
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