Question 13943
{{{3/2y - y = 4 + 1/2y}}} ----->multiply with 2y
{{{3 - 2y^2 = 8y + 1}}}
{{{0=2y^2 + 8y + 1-3}}}
{{{2y^2 + 8y -2=0}}}  ------------------>divide by 2
{{{y^2 + 4y -1=0}}}
{{{y^2 + 4y =1}}}
{{{y^2 + 4y + 4 =1+4}}}
{{{(y+2)^2=5}}}
{{{(y+2)=sqrt(5)}}} or {{{(y+2)=-sqrt(5)}}}
{{{y=sqrt(5)-2}}} or {{{y=-sqrt(5)-2}}}

OK