Question 1085964
{{{x^2+(6-x)^2=28}}}


{{{x^2+36-12x+x^2-28=0}}}


{{{2x^2-12x+8=0}}}


{{{x^2-6x+4=0}}}


{{{x=(6+- sqrt(36-4*4))/2}}}


{{{x=(6+- sqrt(20))/2}}}

{{{x=(6+- 2*sqrt(5))/2}}}

{{{highlight(x=3+- sqrt(5))}}}



You can find each corresponding y coordinate from y=6-x.