Question 1085954


{{{x^2+1300x+1300}}} can be written in the form {{{(x+b)^2+c}}}, where {{{b}}} and {{{c}}} are constants

{{{x^2+1300x+1300}}}....complete square

{{{(x^2+1300x)+1300}}}

{{{(x^2+1300x+b^2)-b^2+1300}}}....since {{{a=1}}},{{{2ab=1300}}}=>{{{b=1300/2}}}=>{{{b=650}}}

{{{(x^2+1300x+650^2)-650^2+1300}}}

{{{(x+650)^2-422500+1300}}}

{{{(x+650)^2-421200}}}->{{{b=650}}} and {{{c=-421200}}} 



and  {{{c/b=-421200/650=-648}}}