Question 1085925


If {{{f(x)=x^2}}} and {{{g(x)=(1/2)x+3}}}, then

{{{ g(f(-1)) =g(((-1)^2))= g(1)}}}

{{{ g(f(-1)) = (1/2)*1+3}}}

{{{ g(f(-1)) = 1/2+6/2}}}

{{{ g(f(-1)) = 7/2}}}