Question 1085895
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The volume of the sphere is {{{(4/3)*pi*r^3}}} = {{{(4/3)pi*4^3}}} = {{{(256/3)*pi}}} cubic units.


The volume of the hollow cone is {{{(1/3)*pi*r^2*h}}} = {{{(1/3)*pi*4^2*5}}} = {{{(80/3)*pi}}} cubic units.


The difference  {{{(256/3)*pi-(80/3)*pi}}} = {{{(176/3)*pi}}} cubic units is the volume under the question.
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