Question 1085292
relation between two numbers: x/y = 3/5 
cross multiply you get, 
5x=3y
x=3y/5

difference between x and y is 40
x-y = 40
substitute x into equation, 
(3y/5)-y=40
y=-100
and back-substitute into x = 3y/5
you get x= -60

check 
-60-(-100)=40
-60/(-100) = 3/5
the answers satisfy all conditions.

if you have alternative methods solving it, i would love to hear from you, thank you
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