Question 1085740
1.{{{C+D+B=67}}}
2.{{{B=2D}}}
3.{{{D=5+C}}}
From 3,
{{{C=D-5}}}
Substitute into 1,
{{{(D-5)+(2D)+D=67}}}
{{{4D=72}}}
Solve for D then use the other equations to solve for C and B.