Question 1085760
Your approach is correct to find the y-coordinates of the intersection points, but there is an error in your arithmetic.
When you substitute x=4 into the equation of the circle, you should get
y^2 - 2y - 8 = 0 and this factors as (y-4)(y+2) = 0
Thus the two intersection points are (4,4) and (4,-2)
We use implicit differentiation to find dy/dx, which is the slope of the tangent line to the circle:
2xdx + 2ydy - 18dx -2dy = 0
-2xdx = (2y-18)dy -> dy/dx = (9-x)/(y-1)
We want to find dy/dx at the points (4,4) and (4,-2)
Substituting the values we get dy/dx @ (4,4) = 5/3 and dy/dx @ (4,-2) = -5/3
To find the equations for the lines, we use the point-slope form:
Line 1: y-4 = (5/3)(x-4) -> y = (5/3)x - 8/3
Line 2: y+2 = (-5/3)(x-4) -> y = (-5/3)x + 14/3