Question 13936
In the formula {{{F=32+(9/5)C}}}, let F = C, and solve:


{{{ C= 32 + (9/5)*C}}}


Multiply both sides by 5:
{{{5C = 160 + 9C}}}

{{{-4C = 160}}}
{{{ C = -40}}}


So, -40 degrees F = -40 degrees C


Check: {{{ F = 32 + (9/5)*C}}}
{{{ F = 32 + (9/5)*(-40) }}}
{{{F = 32 + (9*(-8))}}}
{{{F = 32 - 72= -40 }}}


R^2 at SCC