Question 1085629


if you have:

{{{f(x)=abs(x)}}} and {{{g(x)=5/(x^2+5)}}}

then,

a)

{{{(f*g)(4) =abs(x) (5/(x^2+5))=abs(4) (5/(4^2+5))=4 (5/21)=20/21}}}


b)
{{{(g*f)(2)= (5/(x^2+5))*abs(x)=(5/(2^2+5))*abs(2)=(5/(4+5))*2=(5/9)*2=10/9}}}

c)
{{{(f*f)(1)=abs(x)*abs(x)=abs(1)*abs(1)=1*1=1}}}

d)
{{{(g*g)(0) =(5/(x^2+5))(5/(x^2+5))=(5/(x0^2+5))(5/(0^2+5))=(5/5)(5/5)=1*1=1}}}