Question 1085643
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"If   y + 3x + 2 = 0 and y = x^2", then (substitute !) 

{{{x^2 + 3x +2}}} = 0

with the solutions x= -2 and x= -1  (after factoring  {{{x^2 + 3x +2}}} = (x2)*(x+1)).
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