Question 1085624
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<pre>
{{{2x^2-98}}} = 0  --->

{{{2x^2}}} = 98

{{{x^2}}} = {{{98/2}}} = 49,

x = +/- {{{sqrt(49)}}},

x = +/- 7.


<U>Answer</U>. There are two solutions: x = 7 and x = -7.
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Solved.