Question 1085591
50 is to 80 as X is to 64.
{{{50/80=X/64}}}
{{{X=(50/80)64}}}
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.
{{{d=kr^2}}}
{{{k=d/r^2}}}
So,
{{{50/25^2=Y/50^2}}}
{{{Y=50(50/25)^2}}}
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.
.
{{{D+R=535}}}
and
{{{R=45+D}}}
Substituting,
{{{D+45+D=535}}}
{{{2D=490}}}
Solve for D then use either equation to solve for R.