Question 1085588
Complete the square to get to vertex form.
{{{f(x)=-x^2/4+2x-3}}}
{{{f(x)=-(1/4)(x^2-8x)-3}}}
{{{f(x)=-(1/4)(x^2-8x+16)-3+(1/4)(16)}}}
{{{f(x)=-(1/4)(x-4)^2-3+4}}}
{{{f(x)=-(1/4)(x-4)^2+1}}}
The maximum value (since there is a negative multiplier for the quadratic term) is the vertex value,
{{{y[max]=1}}}
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*[illustration C2.JPG].