Question 1085549
The original circle is centered at (3,5) with a radius of 4.
Reflecting across the y=2 shifts the y coordinate of the center.
The center is 3 units above the line y=2. 
The reflected circle will have the center 3 units below the line y=2.
{{{2-3=-1}}}
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{{{(x-3)^2+(y+1)^2=16}}}
{{{x^2-6x+9+y^2+2y+1=16}}}
{{{highlight(x^2-6x+y^2+2y-6=0)}}}
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I leave it to you to determine the sum {{{B+D+F}}}

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*[illustration C1.JPG].