Question 1085577
Let the fraction be {{{A/B}}}.
So then,
{{{A/(B+1)=-1}}}
{{{A=-B-1}}}
1.{{{A+B=-1}}}
and
{{{(A+1)/B=1}}}
{{{A+1=B}}}
2.{{{A-B=-1}}}
Add 1 and 2,
{{{A+B+A-B=-1-1}}}
{{{2A=-2}}}
{{{A=-1}}}
Now use either equation to solve for B.
{{{-1+B=-1}}}
{{{B=0}}}
So your fraction is an inappropriate fraction, {{{-1/0}}}, since division by zero is not allowed.
I leave it to you to solve for the sum of the numerator and denominator.