Question 96079
4x^2+3=5x
4x^2-5x+3=0
using the quadratic equation we get:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
x=(5+-sqrt[-5^2-4*4*3])/2*4
x=(5+-qrt[25-48])/8
x=(5+-sqrt-23)/8
x=(5+-4.796i)/8
x=(5/8+4.796i/8
x=.625+.599i answer.
x=(5-4.796i)/8
x=5/8-4.796i/8
x=.625-.599i answer.