Question 1085498
Expected value is 120
Can do it by 1 sample proportion (0.4133-0.4)/SE
std error is sqrt (p*(1-p))/300
=0.0283
(0.0133/0.0283)=z
z=0.47
probability z < 0.47 is 0.6808
B
Can use normal approximation
mean is 120
variance is 120*0.6 (np(1-p)=72
sd is sqrt (72)=8.484
(124-120)/8.484=0.4714=z
same answer.
In this instance want something close to 0.5 and greater than.