Question 1085479


{{{f(x)= x^2-3x+9}}} and {{{g(x)= -2x^2+5}}}


 a)
{{{(f+g)(x) = f(x)+g(x)}}}

{{{(f+g)(x) = x^2-3x+9-2x^2+5}}}

{{{(f+g)(x) = -x^2-3x+14}}}


b)

first find {{{(f-g)(x)}}}
{{{(f-g)(x)=f(x)-g(x)}}}

{{{(f-g)(x)=x^2-3x+9-(-2x^2+5)}}}

{{{(f-g)(x)=x^2-3x+9+2x^2-5}}}

{{{(f-g)(x)=3x^2-3x+4}}}

then,

{{{(f-g)(1)=3*1^2-3*1+4}}}

{{{(f-g)(1)=3-3+4}}}

{{{(f-g)(1)=4}}}