Question 1085366

{{{4x + 4=4y}}}.........eq1
{{{y=2x}}}.........eq2
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{{{4x + 4=4y}}}.........eq1..both sides divide by {{{4}}}

{{{x + 1=y}}}.........substitute {{{y}}} in eq2

{{{x+1=2x}}}.........solve for {{{x}}}

{{{1=2x-x}}}

{{{x=1}}}

find {{{y}}}

{{{y=2x}}}.........eq2
{{{y=2*1}}}
{{{y=2}}}