Question 1085356
First find the common ratio, r:
r = (2p-2)/(p-1) = 2(p-1)/(p-1) = 2
Thus r = 2 = (3p-1)/(2p-2) -> 3p - 1 = 4p - 4 -> p = 3
So the 1st 3 terms are 2, 4, 8
Since r > 1, the series does not converge and the sum is infinite.