Question 1085359
1-i=I(1+3i)
I = (1-i)/(1+3i)
multiply numerator and denominator by conjugate 1-3i.  The denominator will become 1-9*i^2=1+9=10
The numerator will be expanded to be 1-3i-i+3i^2=1-4i-3=-2-4i
This is -2-4i/10
divide numerator and denominator by -2
-(1+2i)/5