Question 1085313
<font color="black" face="times" size="3">We start with the first term (a1 = 8). To get the second term we plug it into the generating formula an = 10-3*(a(n-1)) which basically says "current term = 10 minus 3*(previous term)"


The rest of the terms are generated in a similar manner. They depend on the previous term. 


So this is what the first five terms will look like:
a1 = 8
a2 = 10-3*(a1) = 10-3*(8) = -14
a3 = 10-3*(a2) = 10-3*(-14) = 52
a4 = 10-3*(a3) = 10-3*(52) = -146
a5 = 10-3*(a4) = 10-3*(-146) = 448


The first five terms of the sequence are <font color=red>8, -14, 52, -146, 448</font></font>