Question 1085292

let two numbers be {{{x}}} and {{{y}}}

if their a relationship of {{{3:5}}}, we have
{{{x:y=3:5}}}
{{{5x=3y}}}
{{{x=3y/5}}}.........eq1

 and if the difference between them are {{{40}}}, we have

{{{x-y=40}}} 
{{{x=y+40}}}...eq2

from eq1 and eq2 we have: 

{{{3y/5=y+40}}}

{{{3y=5y+200}}}

{{{5y-3y+200=0}}}

{{{2y+200=0}}}

{{{y+100=0}}}

{{{y=-100}}}

find {{{x}}}

{{{x=y+40}}}...eq2

{{{x=-100+40}}}

{{{x=-60}}}

check their difference and relationship :
{{{x-y=40}}} 
{{{-60-(-100)=40}}} 
{{{-60+100=40}}}
{{{40=40}}}

{{{x:y=3:5}}}
{{{-60/-100=3/5}}}
{{{6/10=3/5}}}
{{{3/5=3/5}}}