<PRE><B>Question 1085211</B>
A NORMAL POPULATION HAS STANDARD DEVIATION OF 10. A RANDOM SAMPLE OF SIZE 25 HAS A MEAN OF 50. CONSTRUCT A 95% CONFIDENCE INTERVAL ESTMATE OF THE POPULATION MEAN. 
-----
Sample Mean:: 50
Margin of Error = 1.96*10/sqrt(25) = 3.92
-----
95% CI:: 50-3.92 &lt; u &lt; 50+3.92
------------------
Cheers,
Stan H.
-------</PRE>