Question 1085176
The factors are:
{{{ x - 3 }}} and
{{{ x + 4/3 }}}
{{{ ( x - 3 )*( x + 4/3 ) = 0 }}}
Divide the 2nd factor by {{{ 3 }}}
{{{ ( x - 3 )*( 3x + 4 ) = 0  }}}
{{{ 3x^2 - 9x + 4x - 12 = 0 }}}
{{{ 3x^2 - 5x - 12 = 0 }}}
I can divide by {{{ 3 }}} and get
{{{ x^2 - (5/3)*x - 12 = 0 }}}
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The equations are:
{{{ y = 3x^2 - 5x - 12 }}}
and
{{{ y = x^2 - (5/3)*x - 4 }}} 
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( -4/3, 0 )
{{{ y = 3x^2 - 5x - 12 }}}
{{{ 0 = 3*(-4/3)^2 - 5*(-4/3) - 12 }}}
{{{ 0 = 16/3 + 20/3 - 36/3 }}}
{{{ 0 = 36/3 - 36/3 }}}
OK
( 3,0 )
{{{ y = 3x^2 - 5x - 12 }}}
{{{ 0 = 3*3^2 - 5*3 - 12 }}}
{{{ 0 = 27 - 15 - 12 }}}
{{{ 0 = 27 - 27 }}}
OK
You can check the other form of the equation