Question 1085130
I read this as " the cross section area of a
square rod equals the cross section area of a round rod"
Let {{{ s }}} = a side of the square cross section
The cross section area of the round rod is:
{{{ A = pi*r^2 }}}
{{{ r = 5/2 }}} in
{{{ A = pi*(5/2)^2 }}}
{{{ A = (25/4)*pi }}}
Now I can say:
[ area of square ] = [ area of circle ]
{{{ s^2 = (25/4)*pi }}}
{{{ s = (5/2)*pi }}}
{{{ s = 7.854 }}} in