Question 1084891
For this kind of problem the probability is the number of outcomes that work over the total number of outcomes. The total number of outcomes for two rolls is 

6+5+4+3+2+1=21 This works because: 
(first roll, second roll)

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)= 6 

(2,2) (2,3) (2,4) (2,5) (2,6)=5

(3,3) (3,4) (3,5) (3,6)=4

(4,4) (4,5) (4,6)=3

(5,5) (5,6)=2

(6,6)=1 



Looking at all these possibilities from here we just count the ones that work.

9 sums are greater than 7 so the probability for Event A is 9/21 or 3/7

For Event B there are once again 9 odd sums so the probability is 9/21 or 3/7.

Keep in mind this is if order doesn't matter! (That's why I don't include 6,3 for example since I wrote 3,6 already)