Question 1084983
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M = 2J

M-6 = (J+6)+8 in this equation substitute for M:

2J-6 = J+14.       subtract J from both sides. Add 6 on both sides

J = 20 and the problem says that M has twice as many, so:

M = 20*2 = 40.


Correct answer is M = 40, J = 20.
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