Question 1084946


{{{3(x+8)=6(y+4)}}}......eq.1-> multiply
{{{17y -37 = 3x +7}}}......eq.2...swap sides
-------------------------------------

{{{3x+24=6y+24}}}......eq.1
{{{3x +7= 17y -37 }}}......eq.2
-------------------------------------subtract eq.2 from eq1

{{{3x+24-(3x +7)=6y+24-(17y -37)}}}

{{{3x+24-3x -7=6y+24-17y +37}}}

{{{17=61-11y }}}

{{{11y=61-17  }}}

{{{11y=44  }}}

{{{y=44/11  }}}

{{{y=4  }}}



now, find {{{x}}}

{{{3x+24=6y+24}}}......eq.1

{{{3x=6*4+24-24}}}

{{{3x=24}}}

{{{x=8}}}