Question 1084908
{{{n/d}}}, original fraction


{{{n+4n=20}}}
{{{5n=20}}}
{{{n=4}}}


{{{d+5d=27}}}
{{{6d=27}}}
{{{2d=9}}}
{{{d=9/2}}}




{{{n/d=4/(9/2)}}}


{{{4*2/9}}}


{{{highlight_green(n/d=8/9)}}}
?


check
{{{(8+4*8)/(9+5*9)}}}

{{{40/54}}}

{{{20/27}}}, appears to work.