Question 1084711
({{{-5}}},{{{6}}}) and ({{{2}}},{{{0}}})

first find a slope, then equation {{{y=mx+b}}} of the line that contains given points

{{{m=(6-0)/(-5-2)}}}

{{{m=6/(-7)}}}

{{{highlight(m=-(6/7))}}}


{{{y= -(6/7)x+b}}}........use one point to find {{{b}}}

{{{0= -(6/7)2+b}}}

{{{0= -(12/7)+b}}}

{{{b=12/7}}}

so, your equation is:

{{{y= -(6/7)x+12/7}}}


{{{drawing( 600, 600, -10,10, -10, 10,
circle(2,0,.12), locate(2,0.6,p(2,0)),
circle(-5,6,.12), locate(-5,6,p(-5,6)),
 graph( 600, 600, -10,10, -10, 10, -(6/7)x+12/7)) }}}