Question 1084448
<pre>
{{{"p(A,B)"}}}{{{""=""}}}{{{A*(A^""-1)*(A^""-2)*"..."*(A^""-B+1)}}}

Therefore:

{{{"p(n,n)"}}}{{{""=""}}}{{{n*(n^""-1)*(n^""-2)*"..."*(n^""-n+1)}}}
{{{"p(n,n)"}}}{{{""=""}}}{{{n*(n^""-1)*(n^""-2)*"..."*1}}}{{{""=""}}}{{{n!}}}


{{{2*"p(n,n-2)"}}}{{{""=""}}}{{{2*n*(n^""-1)*(n^""-2)*"..."*(n^""-(n-2)+1)}}}
{{{2*"p(n,n-2)"}}}{{{""=""}}}{{{2*n*(n^""-1)*(n^""-2)*"..."*(n^""-n+2+1)}}}
{{{2*"p(n,n-2)"}}}{{{""=""}}}{{{2*n*(n^""-1)*(n^""-2)*"..."*3}}}
{{{2*"p(n,n-2)"}}}{{{""=""}}}{{{n^""*(n^""-1)*(n^""-2)*"..."*3*2}}}
{{{2*"p(n,n-2)"}}}{{{""=""}}}{{{n*(n^""-1)*(n^""-2)*"..."*3*2*1}}}
{{{2*"p(n,n-2)"}}}{{{""=""}}}{{{n*(n^""-1)*(n^""-2)*"..."*1}}}{{{""=""}}}{{{n!}}}

So they are equal.

Edwin</pre>