Question 1084402


{{{g(x)=  (x+7)/(x^2-13x+40 )}}} ........all values of {{{x}}} that are NOT in the domain of {{{g}}} are values that make denominator equal to {{{zero}}}

so, find {{{x}}} values that make denominator {{{x^2-13x+40=0 }}}

 {{{x^2-5x-8x+40=0 }}}

{{{(x^2-5x)-(8x-40)=0 }}}

{{{x(x-5)-8(x-5)=0 }}}

{{{(x-8)(x-5)=0 }}}

if {{{(x-8)=0 }}}->{{{x=8}}}
if {{{(x-5)=0 }}}->{{{x=5}}}
 both values of {{{x}}} that are NOT in the domain of {{{g}}} 

domain:{ {{{x}}} element {{{R}}} : {{{x<>5}}} and {{{x<>8}}} }