Question 1084378
In the equation log(3)63 - log(3)7 = log(6)x, what is the real value of x? 
I've found that log(6)x = 9
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If it's 
{{{log(3,63) - log(3,7) = log(6,x)}}}
{{{log(3,63/7) = log(6,x)}}}
{{{log(3,9) = log(6,x)}}}
{{{log(6,x) = 2}}}
{{{log(6,x) = log(6,6^2)}}}
x = 36