Question 1084364
{{{f(x)=16^x}}} , {{{g(x)=x/2}}} , and {{{h(x)=(1/8)^x}}}

first, we can find

{{{(f o g)(x)=16^(x/2)=sqrt(16^x)=4^x}}}

now

{{{((f o g)/h)*(x)=4^x/(1/8)^x=4^x/(1/8^x)=32^x}}}