Question 1084312
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Hi, can you please help me solve this world problem for the second part of my homework? 
The boy scouts sold $894 worth of tickets for their spaghetti dinner.  Adult tickets cost $8 each and children’s tickets 
cost $5 each.  If they sold 132 tickets, how many adult tickets and how many children’s tickets were sold?  
a.	Write a system of equations which represents this problem.
b.	Use substitution to solve.
c.	Clearly state the answer to the question.
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Let "x" be the number of adult tickets.
Let "y" be the number of children's tickets.

Then 

 x +  y = 132,     (1)     and
8x + 5y = 894.     (2)


From equation (1), express x = 132 - y and substitute it into equation (2). You will get

8*(132-y) + 5y = 894.


It is a single equation for one unknown y. Simplify and solve it for y:

1056 - 8y + 5y = 894,

-3y = 894 - 1056,

-3y = -162  ---->  y = {{{(-162)/(-3)}}} = 54.


So, 52 children's tickets were sold.


Then the number of adults tickets was 132 - 54 = 78.


<U>Answer</U>.  78 adult tickets and 54 children's tickets were sold.

<U>Check</U>.   78*8 + 54*5 = 894 dollars./  Correct !!
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Solved.