Question 1084269

carpet has a perimeter of {{{P=232in}}}. 

The length {{{L}}} of the carpet is {{{20in}}} more than the width {{{W}}}.

{{{L=W+20in}}}

{{{P=2(L+W)}}}

{{{2(L+W)=232in}}}....substitute {{{L}}}

{{{(W+20in+W)=232in/2}}}

{{{2W+20in=116in}}}

{{{2W=116in-20in}}}

{{{2W=96in}}}

{{{W=96in/2}}}

{{{W=48in}}}

 
{{{L=W+20in}}}

{{{L=48in+20in}}}

{{{L=68in}}}


the dimensions of the carpet are: {{{68in}}} by {{{48in}}}