Question 1084212
you probably want to use a curve fit program.


the relationship is not straight line, but more like a parabola.


using an online curve fit program that i found at <a href = "https://mycurvefit.com/" target = "_blank">https://mycurvefit.com/</a>, i got the following quadratic equation.


y = -.8x^2 + 78x - 4.547474 * 10^-13


i put that equation in the desmos.com calculator and it told me the maximum value for y is at y = 1901.25 when x is at 48.75.


y represents the weekly earnings and x represents the hourly wage.


this means that the amount a repair person makes per week is maximized when the hourly wages he charges is 48.75 dollars per hour.


the desmos.com calculator can be found at <a href = "https://www.desmos.com/calculator" target = "_blank">https://www.desmos.com/calculator</a>


here's what i input into the curve fit program.


<img src = "http://theo.x10hosting.com/2017/060801.jpg" alt="$$$" </>


here's what the curve fit program showed me was the result after i requested a polynomial quadratic equation fit.


<img src = "http://theo.x10hosting.com/2017/060802.jpg" alt="$$$" </>


here's what the desmos calculator showed me.


<img src = "http://theo.x10hosting.com/2017/060803.jpg" alt="$$$" </>


the R^2 tells you how good the fit is.


since the R^2 is equal to 1, that's the best fit you can get.


you could also use excel to do something similar.


they have a correlation option which graphs the data and also tells you which type of equation fits the data the best.


in general, the type of equation that gives you the highest R^2 value is the one that gives you the best fit.