Question 1084086
<pe>
{{{sec(theta)=10}}}

{{{cos(theta)=1/sec(theta)=1/10=0.1}}}

{{{csc^2(theta)=1^""/sin^2(theta)=1^""/(1-cos^2(theta))=1^""/(1-0.1^2)=1/(1-0.01)=1/0.99=100/99}}}

Edwin</pre>