Question 1084178
Radius of the sector is  {{{12/2=6}}}.


Whole circle from the given sector would have area  {{{(22/7)*6^2}}}.


Portion of the circumference which makes the arc on the sector, {{{66/((22/7)*6^2)}}}


{{{(6*11*7)/(2*11*6*6)}}}


{{{7/(2*6)}}}


{{{7/12}}}

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Length of the arc of the sector is  {{{(7/12)*2*(22/7)*6}}}

{{{(7*2*22*6)/(12*7)}}}

{{{2*22*2*3/(2*2*3)}}}

{{{22}}}---------This is the circumference of the cone formed from the sector when folded.


Radius of the cone:
{{{2*(22/7)*r=22}}}


{{{2*r/7=1}}}


{{{highlight(r=7/2=3&1/3)}}}